12w^2+70w-12=0

Solution for 12w^2+70w-12=0 equation:

12w^2+70w-12=0

a = 12; b = 70; c = -12;
Δ = b2-4ac
Δ = 702-4·12·(-12)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-74}{2*12}=\frac{-144}{24}
=-6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+74}{2*12}=\frac{4}{24}
=1/6
$